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P. 23
σ xb ) 23
–
With back tension=(Y’flow
R f
h
φ
−1
tan
H
− ]H b )µ R h f
Entry region
2
=
H
exp [
h ( h b Prof. Ramesh Singh, Notes by Dr. Singh/ Dr. Colton
Y flow )µ − ]H b
′ H
=
p R h f
, )− H µ exp [ α
= α, H = H b ( h exp ⋅ R )µ H b h ( ) −σ xb h b R −1 tan h f
φ ′ Y flow ⋅ C R ( exp h b ′ Y flow = 2 = H b
•at = p = C ( p