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                                                                                         MPa
                      Example 1.6




                                               36                  n  f       1

                                               .                              +          354
                                               0                      Kε
                                               =                              n          =

                                                                       15⋅                                 Prof. Ramesh Singh, Notes by Dr.   Singh/ Dr. Colton
                                            4                                      46  .
                                            .      2                      .        0
                                            1                             1
                                                                        =           36
                                               ln                                    .  )0  46


                                               =                          Y           ⋅      .  1
                                                                      15⋅         (

                                            f       b                     .           720
                                           h       h                      1
                                                                       =
                                               ln                                       15⋅


                                               =                          2τ  flow       .  1

                                               ε  f                                      =
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