( , , ) = ( , , )
∂ ∂
=
∂ ∂
2
2
2
∂(5 − 2 + ) ∂( + + − 30)
∂ = ∂
−2 = (2 )
1
= − (2)
( , , ) = ( , , )
∂ = ∂
∂ ∂
2
2
2
∂(5 − 2 + ) = ∂( + + − 30)
∂ ∂
1 = (2 )
1
= (3)
2
, ) = + + − 30 = 0 (4)
( , 2 2 2
Dari (1) dan (2) diperoleh
=
1
2
5 1
= −
2
5 = −2
2
= − (5)
5
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