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(iii) NH 4NO 3 N 2O + 2H 2O
                 (iv) Fertilizer/expose
                 (c) (i) G or G
                                    -
                      (ii) E 2+ (aq) + 2OH (aq)                E(OH) 2(s)


                                            -
          19.    a)     i) G// G 2(g)    Not G
                               It has the highest potential OR highest reduction potential  1 mark
                        ii) G and N or G 2(g) // N (g)     1 mark

                        iii)




          20.         a)  (i) Cathode – steel
                                Anode – Carbon / graphite
                                             +
                         (ii) To lower the melting P  hence reducing cost of heating the salt.
                      (iii) To prevent the two products from recombining.
                      (iv)  Cathode
                                +
                                      -
                                    Na (l)  + e            Na (l)
                              Anode
                                -
                                        2 Cl (l)                Cl 2 (g) + 2 e-
                 (v) less dense than electrolyte/ has low density
               b)   (i) quantity = 6.42 X 10 60 = 3852
                    (ii)  3852c      province 2.74
                          2X 96000  “         (2 X 96000)  X 2.74
                                                            3852
                                                = 136.58

                        +
                               -
          21.    .a) i) H (aq) + e       ½  H 2

                 ii) E cell = 0.76 + 0.54 = +1.3 volts

                          3+
                 iii) I.  Fe
                     II. Zn
                        3+
                 IV.  Fe  ion
                     3+
                                           2+
                             -
                                               0
                 2 Fe  + 2 e          2 Fe  E  = + 0.77
                                         0
                 2 I            I 2g + 2e E  = - 0.54

                                        2+
                      -
              3+
                                                   0
          2 Fe    + 2I              2Fe     + I  2  E  = + 0.23
                      (aq)
                                        (aq)
              (aq)


          22.    a)     i) Chlorine Has a higher reduction potential
                        ii) +1.36    2.36 = +3.72

                 b)     i) P and S
                        ii)
                        iii) +1.50 – 0.44 + + 1.94

                 c) Q = 4 X a6 X 60 = 3840C
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