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ii) Moles of N = 25 x 0.1 ½
1000
= 0.0025 ½
iii) HCL (aq) + NaOH (aq) NaCL (aq) + H 2O (L)
Balanced ½
State symbols ½
iv) HCL: NaOH 1
1 : 1
Moles of M = 1x0.0025 ½
1
= 0.0025 ½
v) Average titre 0.0025
3
1000 cm ?
= 1000x0.0025 ½
Average titre
= Correct answer ½
vi) Answer (V) x 36.5 ½
1
= Correct answer ½
Table II
a) As in table I
b) Answer in (v) x Titre ½
1000
= Correct answer ½
c) 2HCL (aq) + Na 2CO 3 (aq) 2NaCL (aq) + H 2O (l) + CO 2 (g)
Balanced ½
State symbol ½
d) HCL: Na 2CO 3
2 : 1 1
1x Answer in (b) ½
2
= Correct answer ½
e) 1000 x Answer in (d) ½
25
= Correct answer ½
f) 14.3g/litre 1
g) R + M = Mass in g/h
Molarity
= 14.3 ½
Answer in (e)
= Correct answer ½
h) Answer in (g) = 106 + 18x ½
18x = Answer in (g) – 106
x = Answer in (g) – 106 ½
18
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