4=z2=0=z2=6=z4=0
                                         =z3=7=
        Perform the matrix multiplication,
        Cq(MATRIX)3uOq(MATRIX)4=
        Therefore,
                             0.8 −             −0.4                0            1
                                                                                 
                          ( −0.2               0.6 −            −0.4) ( 2) = 
                                   0           −0.428            1 −            3
        Need to calculate the determinant,
                                 0.8 −              −0.4               0
                                | −0.2             0.6 −            −0.4| = 0
                                       0           −0.428            1 − 
                   = −0.557,                       = 0.808,                    = 2.149
                    1
                                                                                    3
                                                      2
                                                           15