4=z2=0=z2=6=z4=0
=z3=7=
Perform the matrix multiplication,
Cq(MATRIX)3uOq(MATRIX)4=
Therefore,
0.8 − −0.4 0 1
( −0.2 0.6 − −0.4) ( 2) =
0 −0.428 1 − 3
Need to calculate the determinant,
0.8 − −0.4 0
| −0.2 0.6 − −0.4| = 0
0 −0.428 1 −
= −0.557, = 0.808, = 2.149
1
3
2
15