Page 673 - Mechatronics with Experiments
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ELECTRIC ACTUATORS: MOTOR AND DRIVE TECHNOLOGY  659
                             are connected between the OUT1 and OUT2 ports. DC supply voltage and ground are
                             connected to the V and GND terminals.
                                            cc
                                  Logic voltage is internally derived from the V . The operation of the TPIC0107B is
                                                                       cc
                             controlled by two input pins: DIR (IN1) and PWM (IN2). The PWM pin should be connected
                             to the PWM output port of a microcontroller, whereas the DIR pin can be connected to
                             any digital output. The PWM switching frequency is 2 kHz. The state of OUT1 and OUT2
                             (H-bridge output) follows the signal in the PWM pin. The actual PWM signal needs to
                             be formed by the PWM port of the microcontroller. For instance, the current control loop
                             must be implemented in the microcontroller. The IC is capable of sensing over-voltage,
                             under-voltage, short-circuit, over and under current, over temperature conditions and shuts
                             down bridge output and sets the status output pins to indicate the error code (STATUS1 and
                             STATUS2 pins).
                             Example: PM DC Motor       Consider a permanent magnet DC motor. The armature
                             resistance is measured to be R = 0.5 Ω. When V = 120 V is applied to the motor, it reaches
                                                                   t
                                                     a
                             1200 rpm steady-state speed and draws 40 A current. Determine the back EMF voltage, IR
                             power losses, power delivered to the armature, and torque generated at that speed.
                                  The basic relationship for the motor,
                                                             di(t)
                                                    V (t) = L ⋅   + R ⋅ i(t) + V bemf          (8.224)
                                                      t
                                                              dt
                                                   120 V = 0 + 0.5 ⋅ 40 Ω A + V bemf           (8.225)
                                                    V bemf  = 100 V                            (8.226)
                             where the transient effects of inductance is neglected in steady-state. The IR power loss is
                                                           2
                                                                    2
                                                                         2
                                                 P   = R ⋅ i = 0.5 ⋅ 40 Ω A = 800 W            (8.227)
                                                   IR   a
                             and torque generated,
                                                   V bemf   100 V
                                              K =        =                                     (8.228)
                                                E
                                                        ̇  1.2krpm
                                              K = 9.5493 ⋅ 10 −3  ⋅ K Nm/A = 0.7958 Nm/A       (8.229)
                                                                 E
                                                T
                                               T = K ⋅ i = 31.83 Nm                            (8.230)
                                                    T
                             and the electrical power converted to mechanical power,
                                                     P = T ⋅ w                                 (8.231)
                                                       m
                                                        = 4000 W                               (8.232)
                                                        = P e                                  (8.233)
                                                      P = V bemf  ⋅ i a                        (8.234)
                                                       e
                                                        = 100 V ⋅ 40 A = 4000 W                (8.235)
                             Since the motor speed is constant, the motor torque generated by the torque must be used
                             by a total load torque of equal magnitude but in the opposite direction.


                      8.5 AC INDUCTION MOTORS AND DRIVES

                             AC induction motors have been used in constant speed applications in huge quantities. They
                             have been the work horse of the industrial world. In recent years, they have also been used
                             as closed loop position servo motors with a sophisticated current commutation algorithm
                             in the drive being the key to the increased capabilities. Three-phase AC motors are more
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