Page 669 - Mechatronics with Experiments
P. 669

ELECTRIC ACTUATORS: MOTOR AND DRIVE TECHNOLOGY  655
                             The total torque developed as a result of the contribution from each phase is
                                           T = T + T + T  c                                    (8.188)
                                                 a
                                            m
                                                     b
                                                                                     ◦
                                                                       ◦
                                                               2
                                                                             2
                                                         2
                                                  ∗
                                              = K ⋅ i ⋅ (sin    +sin (   + 120 ) +sin (   + 240 ))  (8.189)
                                                 T
                             Note the trigonometric relation,
                                                                      ◦
                                                      ◦ 2
                                                                                   ◦ 2
                                            (sin(   + 120 )) = (cos   sin 120 +sin    cos 120 )  (8.190)
                                                           (√              ) 2
                                                               3      1
                                                         =      cos   − sin                    (8.191)
                                                              2       2
                                                                            √
                                                           3   2    1  2      3
                                                         =   cos    + sin    −  sin   cos      (8.192)
                                                           4        4        2
                                                                            √
                                                           3    2   1   2     3
                                                      ◦ 2
                                            (sin(   + 240 )) =  cos    + sin    +  sin   cos    (8.193)
                                                           4        4        2
                                                                 3
                                                                            2
                                                                     2
                                                             ∗
                                                      T = K ⋅ i ⋅ (sin    + cos   )            (8.194)
                                                       m     T   2
                             Hence, the torque is a linear function of the current, independent of the rotor angular
                             position, and the linearity constant torque gain (K ) is a function of the magnetic field
                                                                       T
                             strength.
                                                             T = K ⋅ i                         (8.195)
                                                              m    T
                             where,
                                                                  ∗ 3
                                                            K = K ⋅                            (8.196)
                                                              T   T
                                                                     2
                                  Therefore, a sinusoidally commutated brushless DC motor has the same linear rela-
                             tionship between current and torque as does the brush-type DC motor. Most implementa-
                             tions make use of the fact that the algebraic sum of three phase currents is zero. Therefore,
                             only two of the phase current commands and current feedback measurements are imple-
                             mented. Third phase information for both the command and feedback signal is obtained
                             from the algebraic relationship (Figures 8.32, 8.33).
                                  Actual back EMF of a real motor is never perfectly sinusoidal nor trapezodial. The
                             ultimate goal in commutation is to maintain a current-torque gain that is independent
                             of the rotor position, that is a constant torque gain. In order to achieve that, the current
                             commutation algorithm must be matched to the back EMF function of a particular motor.
                             Clearly, if a trapezoidal current commutation algroithm is used with a motor which has a
                             sinusoidal back EMF function, the current-to-torque gain will not be constant. The resulting
                             motor is likely to have large torque ripple.
                                  Let us consider the effect of commutation angle error on the current–torque rela-
                             tionship of the motor. Let    be the measurement error in rotor angle. That is    is the
                                                    e                                          a
                             actual motor angle, and     is the measured angle that is used for commutation algo-
                                                   m
                             rithm,    =    −    . It can be shown that the current–torque relationship under non-zero
                                    e   a   m
                             commutation angle error conditions is
                                                         T = K ⋅ i ⋅ cos(   )                  (8.197)
                                                                        e
                                                               T
                                                          m
                             Notice that
                                1. when    = 0, we have the ideal condition,
                                        e
                                             ◦
                                2. when    = 90 , then there is no torque generated by the current,
                                        e
                                3. when −90 ≤    ≤ 90, effective torque constant is less than ideal,
                                              e
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