Page 11 - Flipp Book_T. Asima Sulys Simanjuntak

2. 2(3 + 1) = (2×3 ) + (2×1) = 6 + 2

3. −6(2 − 3) = (-6×2 ) - (-6×3) = -12 + 18

Animated Video discusses Example Questions:

Activity 4 UNDERSTANDING THE DIVISION OF THE ALGEBRA

In the previous three activities, you have discussed addition, subtraction, and multiplication
operations in algebraic forms. In this activity, we will learn the operation of dividing

algebraic forms. The division operation of the algebraic form is the opposite of the
multiplication operation of the algebraic form.

Problem 4.1Division of algebraic forms in

everyday life

If the information in the problem is changed, which is known to be area = x2 + 5x 300 units
of area, and length = x + 20 units of length, you are asked to determine the algebraic form of

the width. How do you go about determining the width?

Solution:

As we know area = length × width. We can write

width =

The width of Pak Tohir's land can be determined by dividing the algebraic form of the land

area by the algebraic form of the length.

2
width = +5 −300 = − 15with x+20≠0
+20
In this activity, we have determined the quotient + 5 − 300 by x + 20 is x 15.
2

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