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36  =  36 ÷ 7   =  4                                                                             SIMPLEST FORM OF A FRACTION Afraction is said to be in the simplest form if the HCF of its
                                  63     63 ÷ 7      7                                                                             numerator and denominator is 1.

                                                             4                                                                     REDUCING A GIVEN FRACTION TO ITS SIMPLEST FORM
                              Hence, the required fraction is     ·
                                                             7
                                                            20                                                                     METHOD               Let the given fraction be  a    and let the HCF of a and b be h.
        EXAMPLE 5:             Write ajraction equivalent to      with denominator 9.                                                                                            b
                                                            36                                                                                                 a      (a ÷ h )
                                   20                                                                                                                   Then,      =            is in the simplest form.
        SOLUTION:              Let      =                                                                                                                      b      (b ÷ h )
                                   36        9                                                                                                                      7
                                                                                                                                   EXAMPLE 8:           Show that      is in the simplest form.
                              Clearly, 9 = 36 ÷ 4.                                                                                                                 10
                              So, we divide the numerator also by 4.                                                               SOLUTION:            Here, numerator = 7 and denominator = 1 0.

                                   20  =   20 ÷ 4  =  5                                                                                                 Factors of 7 are 1, 7.
                                   36      36 ÷ 4     9                                                                                                 Factors of 10 are 1, 2, 5, 10.
                              Hence, the required fraction is    5                                                                                      Common factor of 7 and 1 0 is 1 only.
                                                             9                                                                                          :. HCF of 7 and 10 is 1.
        TO TEST WHETHER TWO GIVEN FRACTIONS ARE EQUIVALENT OR NOT                                                                                                7
                                                                                                                                                        Hence,        is in the simplest form.
                                                                                                                                                                10

                              TEST Let    a  and   c    be two given fractions.                                                                                  21
                                          b      d                                                                                 EXAMPLE 9:           Reduce         to the simplest form.
                              Cross multiply as shown,   a   c                                                                                                   35
                                                       b     d                                                                     SOLUTION:            Here, numerator= 21 and denominator= 35.
                                                 a      c                                                                                               Factors of 21 are 1, 3, 7, 21.
                              If ad = bc, say that   and   are equivalent, otherwise not.                                                               Factors of 35 are 1. 5, 7, 35.
                                                 b      d                                                                                               Common factors of 21 and 35 are 1, 7.

                                          5        20                                                                                                   HCF of 21 and 35 is 7.
        EXAMPLE 5:             Show that      and      are equivalent fractions.
                                          8        32                                                                                                   :. 21       (21 ÷ 7 )      3
        SOLUTION :            The given  fractions  are   5  and  20                                                                                       35   =   (35 ÷ 7 )  =   5  21      3
                                                       8        32                                                                                      Hence, the simplest form of .     is

                              By cross multiplication, we have:    a      c                                                                                                           35      5
                                                                b    d                                                                                                LIKE AND UNLIKE FRACTIONS
                              Now, 5 × 32 = 160 and 8 × 20 = 160.                                                                  LIKE FRACTIONS Fractions having the same denominator are called like fractions.
                                 (5 × 32)= (8 × 20)                                                                                              Thus,   2  ,  4  ,  5  ,  8   are like fractions.

                              Hence,  5   and  20   are euqivalent fraction.                                                                             9    9    9     9
                                      8        32                                                                                  UNLIKE FRACTIONS Fractions having dljferent denominators are called unlike fractions.

        EXAMPLE 6:            Show that  7   and  36   are equivalent fractions.                                                                 Thus,  1  ,  3  ,  5  ,  7   are all unlike fractions.
                                        12        60                                                                                                    2    4     6    9

        SOLUTION:             The given fraction are    7  and  36                                                                 CONVERTING UNLIKE FRACTIONS INTO LIKE FRACTIONS
                                                     12       60
                              By cross multiplication, we have:     7    36                                                        Rule   Suppose some unlike fractions are given. Convert each one of them into an equivalent
                                                               12        60                                                               fraction having a denominator equal to the LCM of all the denominators of the given fractions.
                              Now,   7 × 60 = 420 and 12 × 36 = 432.                                                                                                      1     2      5         4
                                        (7 × 60) ≠ (12 × 36).                                                                      EXAMPLE 10:  Convert the fractions           ,      ,      and    into like fractions.
                                      7        36                                                                                                                         2     3      6         9
                              Hence,      and      are not equivalent fractions.
                                     12        60
                                                                                                                                   SOLUTION:  The given fractions are     1  ,  2   ,  5   and   4
                                                                                                                                                                          2     3      6         9
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