Page 73 - classs 6 a_Neat
P. 73

36  =  36 ÷ 7  =  4  SIMPLEST FORM OF A FRACTION Afraction is said to be in the simplest form if the HCF of its
 63  63 ÷ 7  7  numerator and denominator is 1.

 4      REDUCING A GIVEN FRACTION TO ITS SIMPLEST FORM
          Hence, the required fraction is     ·
 7
 20     METHOD                Let the given fraction be  a    and let the HCF of a and b be h.
 EXAMPLE 5:    Write ajraction equivalent to      with denominator 9.  b
 36                                  a      (a ÷ h )
 20                           Then,      =           is in the simplest form.
 SOLUTION:     Let   =               b      (b ÷ h )
 36  9                                   7
        EXAMPLE 8:            Show that     is in the simplest form.
          Clearly, 9 = 36 ÷ 4.           10
          So, we divide the numerator also by 4.  SOLUTION:    Here, numerator = 7 and denominator = 1 0.

 20  =  20 ÷ 4  =  5           Factors of 7 are 1, 7.
    36  36 ÷ 4  9             Factors of 10 are 1, 2, 5, 10.
          Hence, the required fraction is    5           Common factor of 7 and 1 0 is 1 only.
 9                            :. HCF of 7 and 10 is 1.
 TO TEST WHETHER TWO GIVEN FRACTIONS ARE EQUIVALENT OR NOT  7
                              Hence,        is in the simplest form.
                                      10

 TEST Let   a  and   c    be two given fractions.  21
 b  d   EXAMPLE 9:            Reduce        to the simplest form.
          Cross multiply as shown,   a  c  35
    b  d  SOLUTION:           Here, numerator= 21 and denominator= 35.
 a  c                         Factors of 21 are 1, 3, 7, 21.
          If ad = bc, say that   and   are equivalent, otherwise not.            Factors of 35 are 1. 5, 7, 35.
 b  d                         Common factors of 21 and 35 are 1, 7.

 5  20                        HCF of 21 and 35 is 7.
 EXAMPLE 5:    Show that   and   are equivalent fractions.
 8  32                        :. 21      (21 ÷ 7 )      3
 SOLUTION :    The given  fractions  are   5  and  20  35  =  (35 ÷ 7 )  =  5  21  3
 8  32                        Hence, the simplest form of .     is

          By cross multiplication, we have:    a      c     35     5
 b  d                                       LIKE AND UNLIKE FRACTIONS
          Now, 5 × 32 = 160 and 8 × 20 = 160.  LIKE FRACTIONS Fractions having the same denominator are called like fractions.
               (5 × 32)= (8 × 20)  Thus,  2  ,  4  ,  5  ,  8   are like fractions.

 Hence,  5  and  20   are euqivalent fraction.  9  9  9  9
 8  32  UNLIKE FRACTIONS Fractions having dljferent denominators are called unlike fractions.

 EXAMPLE 6:    Show that  7  and  36   are equivalent fractions.  Thus,  1  ,  3  ,  5  ,  7   are all unlike fractions.
 12  60                       2    4    6     9

 SOLUTION:    The given fraction are    7  and  36  CONVERTING UNLIKE FRACTIONS INTO LIKE FRACTIONS
    12  60
          By cross multiplication, we have:     7  36  Rule   Suppose some unlike fractions are given. Convert each one of them into an equivalent
    12  60     fraction having a denominator equal to the LCM of all the denominators of the given fractions.
          Now,   7 × 60 = 420 and 12 × 36 = 432.  1   2      5         4
  (7 × 60) ≠ (12 × 36).  EXAMPLE 10:  Convert the fractions       ,    ,    and    into like fractions.
    7  36                                      2      3      6         9
          Hence,    and      are not equivalent fractions.
 12  60
        SOLUTION:  The given fractions are     1   ,  2   ,  5  and    4
                                               2      3      6         9
   68   69   70   71   72   73   74   75   76   77   78