Page 78 - AFCAT Solved Papers 2011 - 2019 SSBCrack eBook

59. (d) Let CP = x 62. (b) Let the numbers be 12x and 13x
According to question
-
12x 20 2
Then, =
-
æ 100 ö 13x 20 3
Þ 575 + x = 500 + ç x ÷
è 90 ø Þ 3(12x – 20) = 2(13x – 20)
Þ 36x – 60 = 26x – 40
10x
Þ 575 + x = 500 + Þ 10x = 20
9 \ x = 2
x \ Smallest number = 12x
75 = = 12 × 2 = 24
9
63. (a) According to question
\ x = 75 × 9 = 675 Let the length of train = x meter.
60. (a) Let total amount be x
Therefore,
x
+
Amount spent on food = x 150 x
3 =
22 10
2x 12x = 1500
Amount left =
3 1500
x = = 125 meters.
2x 1 2x 12
Amount spent on rent = ´ =
3 4 12 \ So, length of the train = 125
meters.
6x 64. (a) Let capacity of tank = x
Amount left =
12 According to question,

6x 1 6x x 3x x
Amount spent on cloth = ´ = = - = 22
12 5 60 10 4 5
Therefore,
-
15x 4x = 22
x 2x x 20
x = + + + 1760
3 12 10
11x = 22
x - x - 2x - x = 1760 20
1 3 12 10
´
22 20
\ x = = 40
24x = 1760 11
60 \ Capacity of tank is 40 liters
\ x = 4400
1 1 1 1
61. (a) Here, cost price is not equal to selling price because he 65. (a) Ratio among A, B, C and D = : : :
sells the cloth at 10% loss 3 4 5 6
Using formula; = 20 : 15 : 12 : 10
+
100 G = True Scale So, minimum number of pens = 20 + 15 + 12 +10 = 57
+
100 X False Scale 66. (b) Let sum be x
Here, overall gain (G) = 15% and Loss (X) = –10% (–ve Original Rate = R
sign for loss) 1st Condition:
Let false scale length = l cm Rate of interest = R

+
100 15 100 Time = 4 years
\ =
-
100 10 l 2nd Condition:
Rate of interest increased by 3 = (R + 3)%
90
\ l = ´ 100 = 78.25 cm Time = 4 years
115
\ Actual length of scale is 78.25 cm instead of 1 meter. Therefore,