Page 98 - AFCAT Solved Papers 2011 - 2019 SSBCrack eBook

51. (d) Let Distance travelled by taxi x km and by our car be y Let speed of boat be = x km/hr
km Let speed of stream be = y km/hr
ATQ ATQ
x + y = 80 ......(i) x + y = 6
1.5x + .5y = 50 .....(ii) x – y = 3
Multiplying Eq(i) by .5 and subtracting Eq(ii) from (i) By subtracting
x = 10 2x = 9
Distance travelled by taxi is 10 Km 9 1
52. (b) Let the number be x x = or 4 km / hr
2
2
ATQ 56. (a) A can do a work in 10 day
3 3x 1
x – < 150
4 14 A can do work in 1 day = 10 part of work
3x 1 é 1ù Let B can do in x days
ê – ú < 150
2 2 ê ë 7 ú û in 1 day he can do = 1 part of work
x
é 7 – 2ù A working for 4 day and B for 9 days work is completed
x ê ú < 100
ê ë 14 ú û 4 9
ie ∗ < 1
5 é ù 10 x
x ê ú < 100
ê ë 14ú û 9 6
x = 280 x < 10
53. (d) Let A got = x + 25 x = 15 days
B got = 3x + 25
C got = 2x + 25 Then Both A and B can do in 1 day = 1 + 1 part of
ATQ 10 15
x + 25 + 3x + 25 + 2x + 25 = 735 1
6x = 735 – 75 work = 6
6x = 660 Or they both will complete work in 6 days
x = 110 57. (a) Let the total no. of Mangoes in the crate be x. Then the
Money received by C = 2x + 25
= 2 × 110 + 25 = ` 245 x
no. of bruised Mango =
3 30
54. (b) Amount of water in mixture = ´ 20 < 7.5l
3 ∗ 5 é 1 ù 3
ê as th Mango is bruisedú and every th is
ê ë 30 ú û 4
5
amount of Milk in mixture = ´ 20 < 12.5l unsalable of brused.
8
3 x ö
When 4 litre is drawn out of mixture remaining Mixture Then the unsalable Mangoes = ç æ ç ÷ ÷ < x
ç è
= 16l 4 30ø ÷ 40
3 x
Water amount = ´ 16 < 6l < 12
8 40
x = 480
5
Milk amount = ´ 16 < 10l 58. (a) Let rate of upstream = x kmph and rate of downstream
8 = y kmph
After adding 4 litre of milk Then
Total mixture = 20 l 30 44
Milk = 10 + 4 = 14 l x ∗ y < 10
Water = 6 l
M 14 40 55 13
Ratio = < < 7 : 3 and x ∗ y <
W 6
On solving we get x = 5, y = 11
9
55. (d) Speed of boat upstream = = 3km/hr So, rate of upstream = 5Km/hr and rate of downstream
3 = 11Km/hr

18 1
∴
Speed of boat down stream = = 6 km/hr Rate of current = Ζ11 – 5 < 3 km / hr
3 2