Page 99 - AFCAT Solved Papers 2011 - 2019 SSBCrack eBook

64. (d) Relative speed of both trains = (36 + 45) km/hr
2x
59. (d) Let the sum be x. then SI = 40% of x = Rate = 5%.
5 æ ç 5 ö ÷ m / sec
= ç 81´ ÷
ç è 18ø ÷
é 100 2x 1 ù é 100 S.I ù
´
´
Time = ê ´ ú T ê < ú 45
´
ê ë 5 5x ú û ê ë P R ú û = 2 m / sec
= 8 years Distance travelled by train while passing man = length
60. (c) Correct sum = (36 × 50 + 48 – 23) = 1825. of train.
45
1825 Length of train = ´ 8 < 180m Q (D = ST)
Correct mean = < 36.5 2
50
65. (c) SP of chair = ` 368, Let CP = `x
61. (c) Average score of 10 matches = 38.9 Loss% = 8%
Total score = 38.9 × 10 = 389
é 100 – 8ù
Average score of 6 matches = 42 ê x ú < 368
ê ë 100 ú û
Total score = 42 × 6 = 252
Total score for remaining 4 matches = 389 – 252 = 137 368
x = ´ 100 < 400
92
137
Average for 4 matches = < 34.25 When, profit = 15%
4
115
[ SP = ´ 400 < ` 460
3P 100
62. (b) Let principal be = P, SI =
8 66. (b) Relative speed of train for man = speed of train + speed
of man = (60 + 6) km/hr
1
R = R, T = 6 year æ ç 5 ö ÷ m / sec
4 = ç ç è 66´ 18ø ÷ ÷

PTR 55
SI < = m / sec
100 3
Distance travelled by train while crossing man = length
3P P´ 25 R of train.
´
<
8 100´ 4 Length of train = 110 metres
R = 6% P. a D
63. (b) Let CP of Horse be = ` x Time taken = S

125 110 6 sec
Then SP after getting 25% profit = x = ´ 3 <
100 55
67. (c) 3 men can Plough Field in 43 days, 1 man will plough in
When CP is 200 Less CP = ` (x – 200)
43 × 3
Profit = 30% 4 women can plough in 43 days 1 women will plough in
= 4 × 43 days.
130
SP = (x – 200) Work done by 1 men and 1 women in 1 day
100
1 1
ATQ = +
´
43´ 3 43 4
130 125 Work done by 7 men and 5 women in 1 day
(x – 200) = x – 200
100 100 7 5
= ∗
´
´
130 125 43 3 43 4
x – 260 = x – 200
100 100 1 28 ∗ 15ù 43 1
é
..
= ê ú < <
..
´
5x 43 ê ë 12 ú û 43 12 12
< 60 They will do work in 12 days.
100
x = ` 1200