Page 84 - TUTORIAL MATEMATIKA IPA KELAS XI-2

SUKU BANYAK
36. ( )−2 ( ) = ( )−2 ( ) → ( ) = + 3
2
+ −2 ( +2)( −1)
→ (1) = (1) − 2 (1) = 1 + 3 = 4 … ( )
→ (−2) = (−2) − 2 (−2) = −2 + 3 = 1 … ( )

2 ( )+ ( ) = 2 ( )+ ( ) → ( ) = + 1
2
−3 +2 ( −2)( −1)
→ (1) = 2 (1) + (1) = 1 + 1 = 2 … ( )
→ (2) = 2 (2) + (2) = 2 + 1 = 3 … ( )

6 8
Eliminasi (i) dan (iii) diperoleh : (1) = − ; (1) =
5 5
( ). ( ) 8.(−6) 48
∴ → (1) = (1). (1) = = −
−1 5.5 25

37. ( ) = ( − 1)( − 2)( + 1) ( ) + +
∴ ( ) = +
→ (−1) = − + = 10 … ( )
→ (1) = + = 20 … ( )
Eliminasi (i) dan (ii) diperoleh : a = 5 , b = 15
(2) = 5.2 + 15 = 25

38. ∴ (1) = − + − = 0 → =
2
→ ( ) = − = ( − 1)
∴ (1) =
( )
2
∴ → ( ) = 3 + + 1
( −1)
2
2
2
→ (1) = (1) = 3 + + 1 = → 3 + + 1 = → + 2 + 1 = 0
2
→ ( + 1) = 0 → = −1

5
4
3
4
3
5
39. + −5 + +6 = + −5 + +6
2
−3 +2 ( −2)( −1)
4
3
5
→ (1) = (1) = 1 + . 1 − 5. 1 + . 1 + 6 = 0 → + = −2 … ( )
4
3
5
→ (2) = (2) = 2 + . 2 − 5. 2 + . 2 + 6 = 0 → 16 + 2 = 2 … ( )
3 17
Eliminasi (i) dan (ii) diperoleh : p = , q = −
7 7
3 17
7p – 7q = 7 ( + ) = 20
7 7

4
3
2
40. (2) = 2. 2 − 5. 2 + (2 + 1)2 − 7.2 − 6 = 0
→ 8 − 24 = 0 → = 3
4
3
2
→ ( ) = 2 − 5 + 7 − 7 − 6
Cara Horner
2 2 -5 7 -7 -6

4 -2 10 6 +
2 -1 5 3 0
2
3
Hasil bagi ( ) oleh (x – 2) adalah 2 − + 5 + 3.
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