Page 49 - E-modul Muhammad Aswan_2025_OKTOBER 031025

Langkah 2.
= = (15.9)(2)(0.307) = 9.763 / ²
1
1
= ( + ′ )
1
2
2
= [(15.9)(2) + (19.33 − 9.81)3]0.307
= 18.53kN/m²

Langkah 3.
2 18.53
= = = 0.66
3
1
( − ) (19.33 − 9.81)(3.25 − 0.307)

Langkah 4.
1 1 1
= + + ( − ) ₂ +
2 1 1 1 2 2 2 1 2 2 3
1 1 1
= (9.763)(2) + (9.763)(2) + (18.53 − 9.763)3 + (18.53)(0.66)
2 2 2
= 9.763 + 29.289 + 13.151 + 6.115 = 58.32 /

Langkah 5.

Ambil momen di titik E

1 2 3 1
̅ = [9.763 (0.66 + 3 + ) + 29.289 (0.66 + )]+ [13.151 (0.66 +
58.32 3 2 58.32
3 3
) + 6.115 (0.66 × )] = 2.23
3 2

Langkah 6.
= ( ₁ + ′ ) + ′ ( − )

5
3

2
= [(15.9) (2) + (19.33 - 9.81)3] 3.25 + (19.33 – 9.81) (0.66) (3.25 – 0.307)
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