Page 150 - Pharmaceutical Analytical Chemistry III
P. 150
• Cl- + Ag+ AgCl
• analyte ppt
Fwt=35.5
Wt=? Fwt=143.3
Wt= 0.204gm
GF = a X F.Wt of substance sought (analyte)
b F.Wt of substance weighed (ppt)
GF= (1/1) x (35.5/143.3) = 0.248
Wt of analyte= GF x Wt of ppt
= 0.248 x 0.204 = 0.05 gm Cl-
