Page 143 - NUMINO Challenge_C1
P. 143
Answer Problem solving
Key
1 F C C implies F 1. E E D implies E 2,
Problem solving
D 4 or E 3, D 9. If E 2, F and C in F C E
1 356 188 544 must both be 1, but that is not possible, so E 3,
D 9, and C 2. E D C F B A implies
2 The number that each square represents is A B 13. A and B must be 5, 8 or 6, 7.
In A C B C, only 5, 8 can make A 2 B 2.
shown below.
A 5, B 8, C 2, D 9, E 3, F 1.
15 5 5 5
55 2 implies 0. implies
84 (5 5) 3 5 1 1 4, so it can be 1. The numbers that satisfy are
represented as shown below.
2 and 4. implies 3.
Therefore, 5.
4, 5, 3, 0, 2, 1
Type 2-2 Alphametics p.20~p.21 Creative Thinking p.22~p.23
1 B cannot be 0 in A B B, so A 1. 1 C comes before M in CMLXVII, so 1000 100
2 A 1, so C cannot be 1. If C 2, then D 4. If 900. The sum of L 50, X 10, VII 7, and 900
C 3, then D 9. If C becomes greater, D will is 967. In DCXLVIII, D 500, C 100, X comes
have to be a 2-digit number, so C can only be 2 before L, so 50 10 40, and VIII 8, so the
or 3. sum is 648. The difference between the two
numbers is 967 648 319.
3 A 1, so 1 B C. If C 2, B becomes 1, which Therefore, the answer is CCCXIX.
is the same value as A. Therefore, C 3, B 2,
and D 9. 2 One block in the 1st column on the right
4 Put A and B into . represents 1. One block in the 2nd column
B E B F 2 E 2 F E 4, F 6 or represents 4. One block in the 3rd column
E 5, F 8
But only E 5 and F 8 can satisfy . represents 4 4 16. One block in the 4th
(If E 4 and F 6, then A B E F 1 2
4 6, which is impossible.) column represents 4 4 4 64.
Therefore, E 5 and F 8.
Therefore, represents
64 1 16 1 4 1 1 2 86.
NUMINO Challenge C1
Key
1 F C C implies F 1. E E D implies E 2,
Problem solving
D 4 or E 3, D 9. If E 2, F and C in F C E
1 356 188 544 must both be 1, but that is not possible, so E 3,
D 9, and C 2. E D C F B A implies
2 The number that each square represents is A B 13. A and B must be 5, 8 or 6, 7.
In A C B C, only 5, 8 can make A 2 B 2.
shown below.
A 5, B 8, C 2, D 9, E 3, F 1.
15 5 5 5
55 2 implies 0. implies
84 (5 5) 3 5 1 1 4, so it can be 1. The numbers that satisfy are
represented as shown below.
2 and 4. implies 3.
Therefore, 5.
4, 5, 3, 0, 2, 1
Type 2-2 Alphametics p.20~p.21 Creative Thinking p.22~p.23
1 B cannot be 0 in A B B, so A 1. 1 C comes before M in CMLXVII, so 1000 100
2 A 1, so C cannot be 1. If C 2, then D 4. If 900. The sum of L 50, X 10, VII 7, and 900
C 3, then D 9. If C becomes greater, D will is 967. In DCXLVIII, D 500, C 100, X comes
have to be a 2-digit number, so C can only be 2 before L, so 50 10 40, and VIII 8, so the
or 3. sum is 648. The difference between the two
numbers is 967 648 319.
3 A 1, so 1 B C. If C 2, B becomes 1, which Therefore, the answer is CCCXIX.
is the same value as A. Therefore, C 3, B 2,
and D 9. 2 One block in the 1st column on the right
4 Put A and B into . represents 1. One block in the 2nd column
B E B F 2 E 2 F E 4, F 6 or represents 4. One block in the 3rd column
E 5, F 8
But only E 5 and F 8 can satisfy . represents 4 4 16. One block in the 4th
(If E 4 and F 6, then A B E F 1 2
4 6, which is impossible.) column represents 4 4 4 64.
Therefore, E 5 and F 8.
Therefore, represents
64 1 16 1 4 1 1 2 86.
NUMINO Challenge C1
