Page 157 - NUMINO Challenge_C1
P. 157
Answer
Key
Type 9-1 Application of the Dice “Rule of Seven” p.78~p.79 Type 9-2 Stacking Four Dice p.80~p.81
1 The right face of die has five pips, so using 1 1 2 3 4 5 6 21
the “Rule of Seven,” the opposite face should
have two pips. Since the faces that touch each 2 To make the number of pips on the faces of dice
other have equal pips, then the right face of die , and that meet with die the smallest,
has two pips.
the number of pips should be 1 1 1 3.
2 The number of pips on the top face of die is 4.
Therefore, the number of pips on the base is 3. 3 The sum of the number of pips on two opposite
faces of die is seven. The number of pips on
3 Because the pips are arranged as on the die on the top face should be 1. Therefore, the total
the left, the number of pips on the front of die number of pips on the three faces is 7 1 8.
is 6, and then the face of die that touches
it also has 6 pips. 4 The total number of pips on the 4 die is 21 4
84. The minimum number of pips on faces that
4 When the pips are arranged as on the die on the meet other faces is 3 8 11. Therefore, the
left, the number of pips on the base of die is greatest number of pips on the outside is
2. 84 11 73.
5 Since the number of pips on the base is 2, the Problem solving
number of pips on face A is 5, according to the
“Rule of Seven.” 1 In order to make the total
Problem solving number of pips on the outside
the smallest, you need to have
1 Besides the die on the top, the sum of the pips the most number of pips on
the faces that meet other faces. Then, the
at the base and top of each 4 dice is 7. The number of pips on the faces that meet dice
number of pips on the top face of the die on the and should be 6 each. On die , the sum of
top is 5, so according to the “Rule of Seven,” the number of pips on faces that meet is seven.
the number of pips on the base is 2. Therefore, On die , the number of pips on the faces that
the total number of pips that cannot be seen is cannot be seen is greatest if they are 5 and 6.
7 4 2 30. Then, the total number of pips on the faces that
meet is 6 6 7 (5 6) 30. Therefore, the
2 smallest number of pips on the outside is
21 4 30 54.
6
NUMINO Challenge C1
Key
Type 9-1 Application of the Dice “Rule of Seven” p.78~p.79 Type 9-2 Stacking Four Dice p.80~p.81
1 The right face of die has five pips, so using 1 1 2 3 4 5 6 21
the “Rule of Seven,” the opposite face should
have two pips. Since the faces that touch each 2 To make the number of pips on the faces of dice
other have equal pips, then the right face of die , and that meet with die the smallest,
has two pips.
the number of pips should be 1 1 1 3.
2 The number of pips on the top face of die is 4.
Therefore, the number of pips on the base is 3. 3 The sum of the number of pips on two opposite
faces of die is seven. The number of pips on
3 Because the pips are arranged as on the die on the top face should be 1. Therefore, the total
the left, the number of pips on the front of die number of pips on the three faces is 7 1 8.
is 6, and then the face of die that touches
it also has 6 pips. 4 The total number of pips on the 4 die is 21 4
84. The minimum number of pips on faces that
4 When the pips are arranged as on the die on the meet other faces is 3 8 11. Therefore, the
left, the number of pips on the base of die is greatest number of pips on the outside is
2. 84 11 73.
5 Since the number of pips on the base is 2, the Problem solving
number of pips on face A is 5, according to the
“Rule of Seven.” 1 In order to make the total
Problem solving number of pips on the outside
the smallest, you need to have
1 Besides the die on the top, the sum of the pips the most number of pips on
the faces that meet other faces. Then, the
at the base and top of each 4 dice is 7. The number of pips on the faces that meet dice
number of pips on the top face of the die on the and should be 6 each. On die , the sum of
top is 5, so according to the “Rule of Seven,” the number of pips on faces that meet is seven.
the number of pips on the base is 2. Therefore, On die , the number of pips on the faces that
the total number of pips that cannot be seen is cannot be seen is greatest if they are 5 and 6.
7 4 2 30. Then, the total number of pips on the faces that
meet is 6 6 7 (5 6) 30. Therefore, the
2 smallest number of pips on the outside is
21 4 30 54.
6
NUMINO Challenge C1
