Page 162 - NUMINO Challenge_C1
P. 162
Problem solving 2 Numbers on the diagonal are as follows.

1 The first number in each row has a pattern as 1, 3, 7, 13, 21, 31,

shown below. 2 4 6 8 10
1, 2, 4, 7, 11,
The number in row 9, column 9 is
1234 1 (2 4 6 8 10 12 14 16) 73. The
numbers in the odd-numbered column decrease
The first number in the 10th row is by 1 when you move one space upwards.
11 (5 6 7 8 9) 46. Therefore, the fifth The number in row 6, column 9 is 73 3 76.
number from the left of 10 is 46 4 50.
3 For every 18 counts, the numbers are counted
2 The numbers at the corners are arranged as
with the same fingers. 162 18 9, therefore,
shown below.
2, 3, 5, 7, 10, 13, 17, 21, the index finger of the left hand will be used to

1223344 count 162.

Besides the first addend, the same addend is Left Hand Right Hand
used twice each, and the addends increase by 1.
Therefore, the number at the 16th corner is Thumb Index Middle Ring Little Little Ring Middle Index Thumb
2 (1 2 2 3 3 4 4 5 5 6 6 7 finger finger finger finger finger finger finger finger
7 8 8) 73.
1 2 3 4 5 6 7 8 9 10

18 17 16 15 14 13 12 11

19 20 21 22 23 24 25 26 27 28

36 35 34 33 32 31 30 29

37 38 39 40 41 42 43 44 45 46

Creative Thinking p.100~p.101

1 The numbers at the vertices are divided by 4, 4 Row Column 1 2 3 4

and the numbers with the same remainder are 1 1 4 9 16
2 2 3 8 15
grouped as shown below. 3 5 6 7 14
4 10 11 12 13
Remainder Numbers
0 (A) 0, 4, 8, 12, 16, 20, The numbers on the diagonal have the pattern
1 (B) 1, 5, 9, 13, 17, 21, shown below.
2 (C) 2, 6, 10, 14, 18, 22,
3 (D) 3, 7, 11, 15, 19, 23, 1, 3, 7, 13, 21, 31,

237 4 59 R1. Since the remainder is 1, 237 is at 2 4 6 8 10
vertex B. As the numbers of vertex B (1, 5, 9,
13, ) increase by 4, 237 1 4 59 implies that Therefore, the closest number on the diagonal
the index of 237 is 60. to 93 is 1 (2 4 6 8 10 12 14 16
18) 91, which is the number of row 10, column
10. 93 moves two spaces up, therefore it will be
found in row 8, column 10.

Answer Key
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