Page 72 - PC 101 Interactive practical book
P. 72

MANSOURA NATIONAL UNIVERSIY
         PHARM D- CLINICAL PHARMACY                        LEVEL I                        PHARM. ANAL. CHEM. I (PC 101)



             C Ca al lc cu ul la at ti io on ns s    : :

          Calculations in precipitation titration differ from that in acid-base titration in the


          calculation  of  equivalence  factor  where  (b)  in  precipitation  titration  equals  the

          number of univalent cation atoms present in or equivalent to ONE molecule of the


          standard. In other words, (b) equals the total positive charge on the cation radical


          of ONE molecule of the standard.


                      +1                              +1                            +2
          ex.: For AgNO 3  b = 1,     For NH 4SCN  b = 1,     For Hg(NO 3) 2  b = 2

          For this experiment:
                                             Cl   +  Ag     AgCl 
                                                           +
                                               -
                                               1 AgNO 3 ≡ 1 NaCl
                                                  standard      sample

          Equivalence factor (F):

                                                    1 x M.W. of NaCl x 0.01
              each ml of 0.01 N AgNO 3 ≡                                             ≡ ..........  g NaCl
                                                              1 x 1000


          Concentration:

                                         (E.P.- Ind. blank) x F x 1000
                 Concn. of NaCl =                                               = ..........  g/L
                                                          10

          Results:
             E.P. =


             Concn. =























          72 | P a g e
   67   68   69   70   71   72   73   74   75   76   77