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MANSOURA NATIONAL UNIVERSIY
         PHARM D- CLINICAL PHARMACY                        LEVEL I                        PHARM. ANAL. CHEM. I (PC 101)



                Exp.: Determination of NaCl by Mohr's method




             P Pr ri in nc ci ip pl le e : :


             It  depends  on  the  titration  of  NaCl  sample  with  standard  AgNO 3  using

          potassium chromate (K 2CrO 4) as indicator.


          Titration reaction:

                                               Cl   +  Ag     AgCl 
                                                           +
                                                  -
                                          sample   titrant    white ppt
          End point reaction:


                                               +
                                         2 Ag   +  CrO 4     Ag 2CrO 4 
                                                           --
                                       titrant   indicator      brick red ppt

                                        -                                       +                             --
          In  this  experiment,  Cl   sample  is  titrated  with  Ag   in  presence  of  CrO 4

          indicator where AgCl is precipitated as a white ppt before Ag 2CrO 4 THEN at

                                                                                       +
          the end point (i.e. when Cl  is completely reacted with Ag ), the first slight
                                             -
                                                        --
                           +
          excess of Ag  will react with CrO 4  indicator giving Ag 2CrO 4 (brick red ppt)
          leading to darkening of the yellow color of the solution.


          N No ot te es s: :


            1)  Effect  of  pH:  Mohr's  method  should  be  done  in  neutral  or  slightly

                alkaline medium (pH ≈ 6.5 -9) because:


              At  pH  9:  Ag   will  be  precipitated  as  AgOH  (brown  to  black  ppt)
                                    +
              leading to Consumption of the titrant & Masking of the E.P. color.

                                      Ag   +  OH     AgOH   (brown to black ppt)

                                                   -
                                         +
                                                                        --
              While at pH  6.5: The  chromate  ion  (CrO 4 )  changes  into  acid chromate
                                                          --
                                                                            -
                                                                                       --
              (HCrO 4 ) then to dichromate (Cr 2O 7 ). Both HCrO 4  & Cr 2O 7  form soluble salts
                       -
              with Ag  & so no colored ppt will be formed at the E.P.
                        +
                                         --
                                                                                   --
                                                   +
                                2 CrO 4  + 2 H     2 HCrO 4     Cr 2O 7  + H 2O
                                                                     -
                               chromate               acid chromate      dichromate
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