Page 65 - PC 101 Interactive practical book
P. 65

MANSOURA NATIONAL UNIVERSIY
         PHARM D- CLINICAL PHARMACY                        LEVEL I                        PHARM. ANAL. CHEM. I (PC 101)



          For the second method:


                                 Na 2B 4O 7 + 7 H 2O  2 NaOH + 4 H 3BO 3

                       Boric acid  +  2 glycerol      [Glyceroboric complex] H  +  3H2O


                 [Glyceroboric complex] H  +  NaOH      [Glyceroboric complex] Na  +  H2O
                                                  titrant

                      1 Borax ≡ 4 Boric acid ≡ 4 glyceroboric acid ≡ 4 NaOH

                                                                 1
                                               1 NaOH  ≡    Borax
                                                  standard       4   sample


          Equivalence factor (F):
                                                   1  x M.W. of borax x 0.1

              each ml of 0.1 N NaOH ≡              4                                  ≡ ........  g borax
                                                             1 x 1000

          Concentration:
                                                  E.P 2 x F x 1000
                   Concn. of borax =                                          = ..........  g/L
                                                           10

          Results:

             E.P 1 =


             E.P 2 =

             Concn. of borax (1st method) =


             Concn. of borax (2nd method) =






























          65 | P a g e
   60   61   62   63   64   65   66   67   68   69   70