Page 15 - Mechanics of Structures – Chapter 1

Mechanics of Civil Engineering Structures – Chapter 5

5. To calculate τ 3

S = 70000N

2
A = 200 x 10 = 2000 mm

y = distance of C.G of area considered from N.A 68.18

= (73.18 - 10/2) = 68.18 mm

b = width of section (consider web) = 10 mm

. .
Substitute, τ 2 = . = ( 70000)(2000)(68.18) = 33.39 N/mm
2
6
((28.58 10 )(10))

6. To calculate τ 4

S = 70000N

2
A = 200 x 10 = 2000 mm

y = distance of C.G of area considered from N.A

= (73.18 - 10/2) = 68.18 mm

b = width of section (consider flange) = 200 mm

. . ( 70000)(2000)(68.18)
Substitute, τ 2 = = 6 = 1.67 N/mm
2
. ((28.58 10 )(200))

NHO JKA PSAS Page 15