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′
( ) = ( ) + ( )
′
′ 2
( ) = ( ) + ( )
′ −1
′ + 2
( ) = ( )
′ − 1
Berdasarkan kesamaan dua matriks diperoleh
= + 2 → = − 2
′
′
′
′
= − 1 → = + 1
Substitusi = ′ − 2 dan = ′ + 1 ke persamaan garis 3 + 5 −
7 = 0
′
′
3( − 2) + 5( + 1) − 7 = 0
′
′
3 − 6 + 5 + 5 − 7 = 0
′
3 + 5 − 8 = 0
′
Jadi persamaan bayangan garis adalah 3 + 5 − 8 = 0
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