1. |2x – 1| = 7 Alternatif Penyelesaian 2 (2x −1) = 7 2 2 4x – 4x + 1 = 49 2 4x – 4x + 1 – 49 = 0 2 4x – 4x – 48 = 0 x – x – 12 = 0 2 (x – 4)(x +3) = 0 x = 4 atau x = -3 2. |2x – 1| = |x + 3| (Dikerjakan sebagai latihan) 24 Kelas X SMA/MA/SMK/MAK