G Lihat segitiga ABG Sin A = BG = BP AG AB 6√2 P ? 6 2 = BP A 6 B 6 3 6 2 BP = 6 ( 2 )( ) 6 x 3 = 6 6 6 3 3 3 BP = 2√6 Jadi jarak B ke AG = 2√6 cm 22