Page 22 - Dimensi Tiga XII (Nurul Hidayati)
P. 22
Pembahasan
Jarak A ke TC = AP
AC = diagonal persegi
T
= 12√2
AP = AC − PC 2
2
P = ( 12 ) 2 2 6 ( − ) 2 2
= 2 ( 144 − 36 ) = . 2 108
D C = . 3 . 2 36 = 6 6
Jadi jarak A ke TC
A 12 cm B = 6√6 cm
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