Page 80 - E-modul Mekanika Teknik 2 Fase E/Kelas X SMK

Momen Inersia akan sumbu x:
Ix = I2x + Fb 2
2
3
2
Ix1 = 1/12 . 6 cm . (2 cm) + 12 cm . (4 cm) = 4 cm + 192 cm = 196
4
4
cm 4
Ix2 = 1/12 . 2 cm . (6 cm) + 12 cm . (0 cm) = 36 cm + 0 cm = 36 cm 4
3
2
4
4
2
3
2
4
4
2
Ix3 = 1/12 . 6 cm . (2 cm) + 12 cm . (4 cm) = 4 cm + 192 cm = 196
cm 4
4
Jadi Ix = 428 cm
Momen Inersia akan sumbu y:
Iy = I2y + F.a 2
2
4
Iy1 = 1/12 . 2 cm . (6 cm) + 12 cm . (2 cm) = 36 cm + 48 cm = 84 cm 4
2
3
4
4
4
Iy2 = 1/12 . 6 cm . (2 cm) + 12 cm . (0 cm) = 4 cm + 0 cm = 4 cm
3
2
4
2
4
3
4
2
2
Iy3 = 1/12 . 2 cm . (6 cm) + 12 cm . (2 cm) = 36 cm + 48 cm = 84 cm 4
4
Jadi Iy = 172 cm

D. JAWABAN SOAL EVALUASI AKHIR
1. B
2. A
3. C
4. D
5. D
6. E
7. E
8. C
9. B
10. A
11. A
12. B
13. E
14. C
15. B
16. D
17. A
18. E
19. A
20. E

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