Page 22 - suhu & kalor

5.1
5. Perubahan Wujud Zat Tugas Anda 7.2
)4;07 =30 ?4;090@8 107E0 H0B 30?0B 14@14=BC: B860 EC9C3 G08BC
?030B 208@ 30= 60A :810B ?4=60@C7 AC7C EC9C3 H0B 30?0B 14@C107 Seperempat kilogram es, dengan
suhu –10°C, dicampur dengan 2 kg
30@8 EC9C3 ?030B <4=9038 208@ 30= 30@8 208@ <4=9038 60A 0B0C A410;8:=G0 air yang suhunya 20°C. Diskusikan
-0B A4;0;C <4=4@8<0 0B0C <4;4?0A:0= :0;>@ A4;0<0 ?4@C1070= EC9C3 dengan teman sebangku Anda,
bagaimana fase akhir campuran
14@;0=6AC=6 B4B0?8 B830: 38A4@B08 34=60= :4=08:0= 0B0C ?4=C@C=0= AC7C tersebut dan berapakah suhu akhir
(410608 2>=B>7 :4B8:0 4A A430=6 <4=208@ B4@9038 ?4@C1070= EC9C3 30@8 campuran tersebut?
?030B <4=9038 208@ &030 ?4@8AB8E0 B4@A41CB 381CBC7:0= A49C<;07 :0;>@
B4B0?8 B830: 38A4@B08 34=60= :4=08:0= AC7C
5.1
&4;090@8 3806@0< ?030 ".#"3 &4@C1070= EC9C3 30@8 208@ :4 60A menyublim menguap
38A41CB # $ * & &@>A4A A410;8:=G0 30@8 60A :4 208@ 38A41CB # $ # *$ Gas
&@>A4A ?4@C1070= EC9C3 30@8 ?030B :4 60A 38A41CB # $.* " # &@>A4A menyublim
mengembun
A410;8:=G0 30@8 60A :4 ?030B 38A41CB # $.* " #
Padat Cair
a. Kalor Uap dan Kalor Embun mencair
8:0 =30 <4=4B4A:0= A?8@8BCA ?030 :C;8B B0=60= 10680= :C;8B G0=6 membeku
38B4B4A8 A?8@8BCA 0:0= B4@0A0 38=68= 0; B4@A41CB 38A4101:0= :0;>@ ?030 5.1
10680= :C;8B B0=60= G0=6 38B4B4A8 A?8@8BCA 38A4@0? >;47 A?8@8BCA C=BC: Gambar 7.2
Diagram perubahan wujud zat
<4=6C0? 0=G0:=G0 :0;>@ G0=6 38?4@;C:0= C=BC: <4=6C0?:0= A?8@8BCA
A410=38=6 34=60= <0AA0 A?8@8BCA 30= 14@60=BC=6 ?030 :0;>@ ;0B4= C0?
:0;>@ C0? A?8@8BCA B4@A41CB
"%' * & 030;07 ! "%' . $ & '"*! $ *$)*! # $ * ,* * ! / ) cobalah kalian kerjakan soal
' # $ * & & ) ) ! $. 30?C= ! "%' # *$ 030;07 : "%' . $ di link berikut :
" & ( *$)*! # $ * ,* * ! * & # $ ' & ) ) ! " *'$.
!0;>@ C0? AC0BC H0B A0<0 14A0@ 34=60= :0;>@ 4<1C= H0B B4A41CB #8A0;=G0
:0;>@ C0? @0:A0 :6 :0;>@ 4<1C= @0:A0 ?C= :6
8:0 :0;>@ C0? :0;>@ 4<1C= AC0BC H0B 030;07 C=BC: <4=6C0?:0=
<4=64<1C=:0= H0B G0=6 <0AA0=G0 # 0:0= <4<4@;C:0= :0;>@ A410=G0:

# (6) J
*
34=60= 030;07 :0;>@ C0? :6
*
5.1
"#&- <4<?4@;870B:0= B8B8: 38387 30= :0;>@ C0? 14@10608 H0B
?030 B4:0=0= 0B<>A54@ &4;090@8 B014; B4@A41CB H0B <0=0:07 G0=6 <4
<8;8:8 :0;>@ C0? B4@14A0@
"#&-
5.1
)8B8: 8387 30= !0;>@ *0? 4@10608 -0B &030 )4:0=0= 0B<
*5*, %*%*) "-03 %*%*)
!"5
; ,(
4;8C< J K
83@>64= J K
$8B@>64= J K
%:A864= J K
;:>7>; K
'0:A0 K
8@ K
(C;5C@ K
)8<07 78B0< K
=B8<>= K
&4@0: K
<0A K
)4<1060 K
Sumber: Physics, 1980

151
Kalor 17