Page 37 - Pharmaceutical_Analytical_Chemistry_1_Theoretical_Notes_Level_1 2024-2025
P. 37

Mansoura National University
            Pharm D-Clinical Pharmacy Program                 Level 1             Pharm. Anal. Chem. 1 (PC 101)

                                         ▪  What is the ratio of sodium to salt?

                              Na CrO   +  Pb(NO )  → PbCrO    +  2NaNO
                                  2      4                3 2                4                 3

                                      1 mole  + 1 mole         →    1 mole    +    2 moles
                                     162 g    +    331 g           →    323 g    +     170 g (85 g X 2)


                                   0.1 mole  + 0.1 mole         →    0.1 mole    +    0.2 moles
                                     16.2 g    +    33.1 g           →    32.3 g      +     17.0 g
               Molar ratio


                     1 Na2CrO4 : 1 Pb(NO3)2                 1 Na2CrO4 : 2 NaNO3


                                      Na CO   +  CaCl     → CaCO   +  2NaCl
                                         2    3           2              3
                                         1 mol       1 mol        1 mol        2 mol
                      - How many mL of 0.25 M CaCl  are needed to react completely with 50
                                                          2
                      ml of 0.15 M Na CO ?
                                        2    3

                         Solution


               No. moles of Na 2CO 3 = M  x  V L
                                                                            V of CaCl =?? mL
                                                                                      2
                  = 0.15 M Na 2CO 3  x  (50 /1000).                         Molarity of CaCl = 0.25
                                                                                             2
                              -3
                  = 7.5  x  10  mol Na 2CO 3 .                              V of Na CO = 50 mL
                                                                                    2
                                                                                        3
                                                                            Molarity of Na CO =  0.15
               Therefore, the no. of moles of CaCl 2 needed will                           2   3
               be also


                          -3
               7.5  x  10  mol .

               V L= No. moles of CaCl 2 / M


               V L = 7.5  x  10  / 0.25 = 0.03 L =  30 mL
                                -3







                                                             15
   32   33   34   35   36   37   38   39   40   41   42