Page 36 - مشروع تخرج 1
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For a given data P=0.4 bar, saturated, from appendix A-2


                        Saturated liquid               Saturated vapor


                  ℎ                    . = 459.61    /       ℎ                    .= 2690.4    /    

                                                                  o
                                   o
                          T=109.55  c                    T=109.55  c





               Mass flow rate (m ̇ ) of outlet liquid is given by the equation



                                    ℎ            − ℎ                    .
               ṁ = ṁ            ∗                                                          (3.12)
                                 ℎ                    . −ℎ                    .



                         6
                     = 10 ∗   461.47−2690.4  = 999166.214     /ℎ  
                              459.61−2690.4
               Mass flow rate (m ̇ ) of outlet vapor is given by the equation



               m = m            − ṁ                    .                           (3.13)
                       ̇
                 ̇
                         6
                    = 10 − 999166.214 = 833.78     /ℎ  





                 nd
               2   stage  ( 0.3 bar ) :                                          m steam= 4082kg/hr


                 T =109.55°c                                                T =107.38°c
                                                   nd
                                                  2   stage
                 P =1.5 bar                        0.3 bar                  P =0.3 bar
                 m= 0.999 Mkg/hr                                            m= 0.995 Mkg/hr










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