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Ques.    Comment                                        Recommendation
                                                                          anyone.
                                                                         Wash hands and face after
                                                                          use of the source.
                                                                         Keep  the  source  away
                                                                          from the body.
                (c)(iii)  “….  Total  mass  of  elements….”.  This  will  Credit  should  be  given  for
                         mean only the Barium and Krypton since the  both  …  including  the
                         neutron is not an element                      neutron  and  not  including
                                                                        the neutron
                                                                        Either: Mass of [Ba + Kr +
                                                                                              -27
                                                                        3n]  =    390.190  x  10   kg
                                                                                        -25
                                                                        OR 3.90190 x 10  kg
                                                                        OR:  Mass  of  [Ba  +  Kr  ]  =
                                                                                      -27
                                                                        385.180  x  10   kg      OR
                                                                                    -25
                                                                        3.85180 x 10  kg
                4b(ii)   2013 Syllabus Section A                         Students  could  have  used
                         Specific  Objective  4.1  define  the  terms:    average  velocity v̅ =  0+18
                         distance,  displacement,  speed,  velocity,      = 9 ms                 2
                                                                                -1
                         acceleration; Distance and displacement, s or    And distance x = v̅ t = 9 x
                         x; speed and velocity, v; acceleration, =  − .
                                                                        18 = 16.2 m
                         Specific  Objective  4.2  apply  displacement-   But  Average  velocity  is
                         time  and  velocity-time  graphs;  Finding  the   NOT  MENTIONED  on
                         gradient for straight lines only                 the syllabus.
                         Equations of motion are NOT on the syllabus,    If  students  had  been
                         so student cannot use them to find distance.      advised  to  sketch  a
                                                                           velocity-time  graph  and
                                                                           hence find distance, they
                                                                           would have been  able to
                                                                           find  distance  from  the
                                                                           area  under  the  graph  =
                                                                                            1
                                                                           area of triangle =   X 1.8
                                                                                            2
                                                                           x 18 = 16.2 m
                                                                        What will you give students
                                                                                       
                                                                        who wrote v =
                                                                                       
                                                                        x = v t = 18 x 1.8 = 32.4 m ?
                5a        Will  students  understand  that  “appropriate  (a)(i) Car radiator: [any 2?]
                           characteristics”  means  rough  or  smooth,  Nature  :  Dull  –  Emits
                           etc.?                                        radiation                (to
                          The  statement  is  ambiguous.  Since  two  surroundings)/         Good
                           cases are given students may give one factor  emitter
                           for each case.                               Colour  :  Black  –  Emits




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