Page 12 - BUKU MANDAILING KLS 7 BAB VI
P. 12

b.  Apabila       ∶      =      ∶      maka      ∶      =      ∶     


            Pembuktian :

                  ∶      =      ∶       ⇔          =              (                                )

                                 ⇔          =               (                                    )


                                        
                                 ⇔  =              (                                                                       )
                                        
                             ,      ∶      =      ∶       ↔       ∶      =      ∶       (                                )


                c.  Apabila      ∶      =      ∶                       (     +     ) ∶      = (     +     ) ∶     


            Pembuktian :


                  ∶      =      ∶       ⇔          =                                              (                                )

                                 ⇔          +          =          +                        (                            ℎ         )

                                 ⇔ (     +     ) .       =      . (     +     )      (                                                                 )


                                  +           +    
                                 ⇔  =                                    (                                )
                                          
                             ,      ∶      =      ∶       ⇔ (     +     ):      = (     +     ) ∶       (                                )



                d.  Apabila      ∶      =      ∶                       (      −      ) ∶      = (     −      ) ∶     


            Pembuktian :


                                    =
                                       
                  ∶      =      ∶       ⇔
                                        
                                 ⇔ − 1 =  −  1                          (                                                     )
                                           
                                  
                                           
                                 ⇔ −  =  −
                                  
                                           
                                               
                                      
                                                    
                                  −            −     
                                 ⇔  =                                    (                                )
                                           
                             ,      ∶      =      ∶       ⇔ (     −     ):      = (     −     ) ∶       (                                )





                                                                                 BAB 6 Perbandingan  151
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