Page 3 - ECAT Past Paper 2006
P. 3

ECAT PAST PAPER-2006                                                 BY www.studyplex.net



                              5=√   +      −             
                              :.Squaring both sides:
                              25= 25-24cos  
                              cos  =0
                                =π/2 (Answer)
               Q.3     A body starting from origin first of all moves 10m towards North then 15m towards east
                       and finally moves 20m vertically upwards. What is the total displacement?
                       A) 30m (Correct)                                  B) 26.92m
                       C) 18.02m                                         D) 25m
                       Explanation:























               Q.4     The acceleration produced varies directly with:
                       A) Mass                                           B) Torque
                       C) Applied Force (Correct)                        D) Friction
                       Explanation:
                                                    nd
                              According to Newton’s 2  Law of motion:
                              F=ma
                                      
                              :. A∝
                                     
                              :. A∝   
               Q.5     When the velocity of a body is doubled then:
                       A) its K.E is doubled                             B) its P.E is doubled
                       C) its momentum is doubled (Correct)       D) its acceleration is doubled
                       Explanation:
                              As we know that:
                              p=mv  as v’=2v so p’= m(2v) p’=2p (Answer)
               Q.6     1 kg mass has K.E of 1 J then its speed is:
                       A) 1m/s                                    B) 4.4 m/s
                       C) 1.4 m/s (Correct)                              D) 2.5 m/s
                       Explanation:
                              As we know that:
                                        2
                              K.E= ½ mv
                                       2
                              1= ½ (1) v
                                 2
                              2=v v=1.41 m/s (Answer)
               Q.7     If θ=180* then Work done=?
                       A) 0                                              B) Maximum
                       C) Negative (Correct)                             D) -1
                       Explanation:
                              As we know that:
                              Work done=Fdcosθ
   1   2   3   4   5   6   7   8