Page 7 - ECAT Past Paper 2006
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ECAT PAST PAPER-2006                                                 BY www.studyplex.net



               Q.25  A small parallel resistance (shunt) used to convert galvanometer into an ammeter of
                       suitable range is given by:
                       A) Rs=        ∗                                   B) Rs=        ∗      (Correct)
                               +                                                 −    
                       C) Rs=   +      ∗                                 D) Rs=         −     
                                                                                  −    
                       -Self Explanatory.
                              For your information:
                              1) Range of an Ammeter: Rs=       
                                                           −1
                              2) Range of a Voltmeter: Rh=(n-1) Rg
               Q.26  Permeability of free space is given by:
                                                                                    -7
                               -7
                       A) 4π*10  Wb/Am (Correct)                         B) 1/4π *10 Wb/Am
                               -3
                       C) 2π*10 Wb/Am                                    D) None of these
                       -Self Explanatory.
               Q.27  An inductor of 1 henry is connected across a 220 V,50 Hz supply. The peak value of
                       current is:
                       A) 0.5 A                                          B) 0.7 A
                       C) 1 A (Correct)                                  D) 1.4 A
                       Explanation:
                              As we know that:
                              XL=2πf L
                              XL=2*3.14*50*1
                              =100*3.14
                              =314 Ohm
                              We also know that:
                              Irms=Vrms/XL
                              Irms= 220/340
                              Irms=0.70 A
                              As we are to find the peak value of current so:
                              Irms= Io/√2
                              0.70*√2=Io
                              Io= 0.9899 A
                              Io=1 A (Approx)
               Q.28  Transistor is basically a:
                       A) Voltage amplifier (Correct)             B) Current amplifier
                       C) Rectifier                                      D) None of these
                       Explanation: As we know that the gain of amplifier is given by:
                       A=-βRc/rie
                       The value of the factor βRc/rie is of order of hundred so the input voltage is amplified thus
                       transistor is basically a voltage amplifier.
               Q.29  Hydrogen is also called
                       A) Deuterium                                      B) Tritium
                       C) Protium                                        D) All of these (Correct)
                       -Self Explanatory.
               Q.30  Rate of decay of radio active element ____ with time:
                       A) increases                                      B) decreases (Correct)
                       C) remains same                                   D) All of these
                       Explanation:
                              As we know that:
                                   −∆  /  
                              :.   =
                                     ∆  
                              As t increases so that rate of decay decreases
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