Page 11 - Microsoft Word - E-Modul SPLTV

Langkah 4: substitusik nilai z = (6), :

⟹ −33y + 54Z = − 63
72
⟹ −33y + 54 = − 63
11
3.888
⟹ −33y + = − 63
11
⟹ + . = − 63

363 3.888
⟹ = − 63 −
11 11
363 693 3.888
⟹ = − −
11 11 11
363 4.581
⟹ = −
11 11
−4.581
11
⟹ =
363
11
4.581 11
⟹ = ×
11 363
4.581
⟹ =
363
.
Langkah 5: substitusi = dan Z = ke persamaan (7), menjadi:

=

4.581 72
9 − 3( ) + 4 ( )
= 363 11
2
4.581 72
9 − 3( ) + 4 ( )
= 363 11
2
13.743 288
9 − +
= 363 11
2
3.267 − 13.743 + 9.504
363 363 363
=
2
− 972
363
=
2

= x 2