Page 155 - Linear Models for the Prediction of Animal Breeding Values 3rd Edition
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12.0
             11.0
             10.0
              9.0
            variance (kg 2 )  7.0
              8.0

              6.0

            Daily  5.0
              4.0
              3.0
              2.0
              1.0
              0.0
                 7   28  49   70  91  112  133  154  175  196  217  238  259  280  301
                                           Days in milk

                                     Genetic   Permanent environment
        Fig. 9.1. The estimates of daily genetic and permanent environmental variances by days
        in milk.
                                                    −1
            For all animals with records,  Q′ R Q =  Z′ R Z and are block diagonal. For
                                           −1
                    −1
        instance, Q′ R Q for the first three cows (cows 4, 5 and 6) with records is:
            ⎡ 1.348 0.000 0.335 0       0      0       0       0       0    ⎤
            ⎢                                                               ⎥
            ⎢ 0.000 1.647 0.000 0       0      0       0       0       0    ⎥
            ⎢ 0.335 0.000 2.035 0       0 0    0       0       0       0    ⎥
            ⎢                                                               ⎥
            ⎢ 0     0      0      1.348 0.000 0.335    0       0       0    ⎥
            ⎢ 0     0      0      0.000 1.647 0.000    0       0       0    ⎥
            ⎢                                                               ⎥
             0 ⎢    0      0      0.335 0.0000 2.035   0       0       0    ⎥
            ⎢                                          0.674 −              ⎥
            ⎢ 0     0      0      0     0      0               0.648   0.167 ⎥
             0 ⎢    0      0      0     0      0      − 0.648  0.824 − 0.591⎥
            ⎢                                                               ⎥
            ⎣ 0     0 0    0      0     0      0       0.167  − 0.591  1.018 ⎦
                                         −1
        When all animals are considered, Q′R Q is augmented by nr columns and rows per
                                                                           −1
                                                        −1
        ancestor without records (i.e. animals 1−3). The matrix G  is then added to Q′R Q and
                       −1
          −1
        P  added to Z′R Z to obtain the MME. Solving the MME by direct inversion with the
        solution for level 10 of HTD effects constrained to zero gave the following results:
        Effects      Solutions
        HTD
           1         10.0862
           2          7.5908
           3          8.5601
           4          8.2430
                                                                         Continued

        Analysis of Longitudinal Data                                        139
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