Page 109 - Grade 10 C.Math
P. 109
pbfx/0f 3
2
4
3
n=;= lgsfNg'xf];\ M x – 1 / x + x + 1
;dfwfg
oxfF, klxnf] cleJo~hs = x – 1
3
Curriculum Development Centre
2
= (x - 1) (x + x + 1)
bf];|f] cleJo~hs = x + x + 1
2
4
= (x + 1) – 2x + x 2
2
2
2
2
= (x + 1) – (x) 2
2
2
2
= (x + x + 1) (x – x + 1)
n=;= = -;femf u'0fg v08_ x afFsL u'0fg v08x¿
= (x – x + 1) (x – 1) (x + x + 1)
2
2
2
= (x–1) (x + x + 1) (x – x + 1)
2
pbfx/0f 4
3
2
3
4
3
2
n=;= kTtf nufpg'xf];\ M x – 1, x + x + x / x – x + x
;dfwfg
oxfF, klxnf] cleJo~hs = x – 1
3
= (x –1) (x + x + 1)
2
3
4
bf];|f] cleJo~hs = x + x + x 2
2
= x (x + x + 1)
2
t];|f] cleJo~hs = x – x + x = x(x – x + 1)
3
2
2
n=;= = ;femf u'0fg v08 X afFsL u'0fg v08x¿sf] u'0fg kmn
= x (x - 1) (x + x + 1). x(x - x + 1)
2
2
2
= x (x +1) (x + x + 1) (x – x + 1)
2
2
pbfx/0f 5
2
2
3
4
3
n=;= kTtf nufpg'xf];\ M x + 10x + 169, x + 4x + 13x / x + x(x + 13) + 3x 2
;dfwfg
oxfF, klxnf] cleJo~hs = x + 10x + 169
2
4
= (x ) + 169 + 10x 2
2 2
= (x + 13) – 26x + 10x 2
2
2
2
106 ul0ft, sIff – 10
