Page 92 - Grade 10 C.Math
P. 92

pbfx/0f 6
                        lrqdf b]vfOPsf] ;+o'St 7f]; j:t'sf] k'/f cfotg lgsfNg'xf];\ M






                          Curriculum Development Centre



                             2.75 ld=                         2.5 ld=









                                          0.5 ld=
                        ;dfwfg

                        oxfF lk/fld8 cfsf/sf] :t'ksf] prfO (h ) = (2.75 - 2.5) ld6/
                                                         1
                                                            = 0.25 ld6/
                        :t'ksf] cfwf/ e'hf (a) = 0.5 ld=

                        if8\d'vfsf/ 7f]; j:t'sf] prfO (h ) = 2.5 ld=
                                                    2
                        if8\d'vfsf/ 7f]; j:t'sf] cfwf/sf] e'hf (a) = 0.5 ld=

                                     '
                                       ]
                                                {
                                                                         '
                                                                                    ]
                                                                        \
                                                           ]
                                                                ]
                               ]
                          '
                         +
                        ;oSt 7f; j:tsf cfwf/ jufsf/ 5, h;sf tNnf efu if8dvf / dflyNnf efudf lk8fld8 5 .
                        7f]; j:t'sf] k'/f cfotg (V)    = (a  h  +   a h )
                                                       2
                                                                2
                                                          2
                                                                  1
                                                          = a (h  +  h )
                                                      2
                                                         2     1
                                                    = (0.5 ld)  [2.5  +  x 0.25] ld=
                                                            2
                                                    =                3g ld=
                                                         
                                                    =          3g ld=
                                                   =        3g ld=
                                                    = 0.6458 3g ld=

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