Page 105 - Distribusi peluang binomial
P. 105

x = 1                                                      x = 5                                                           1

                                                                                                                                          f x =                                              x + 2






                                7                                                                               C                                                        20






                              20                                                                                                                                                                              1




                                                                                                                                                     P(1 < X < 5) =  (AD + BC) AB

                                                                                                                                                                                                              2




                                3                      D                                                                                                                                                       1                                          3





                             20                                                                                                                                      AD = f 1 =                              20           1 + 2 =                       20








                                                                                                                                                                                                                1                                           7




                                                       A                                                        B                                                    BC = f 5 =                              20            5 + 2 =                        20







                                                                                                                                                                     AB = 5 − 1 = 4
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