Page 106 - Distribusi peluang binomial

x = 1 x = 5 1

f x = x + 2

7 C 20

20 1

P(1 < X < 5) = (AD + BC) AB

2

3 D 1 3

20 AD = f 1 = 20 1 + 2 = 20

1 7

A B BC = f 5 = 20 5 + 2 = 20

AB = 5 − 1 = 4