Page 13 - 6- اجابات نيوتن

‫إجابات‬
‫الفصل‬
‫الثانى‬

F = F +F

F =  I1I2L  BI2L2
2d

 F = 4 107  5 6 1  2.5105  6 1
2  0.4

 F = 1.65  10-4 N

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 = BIAN sin 
 = 0.4  10  0.2  200  sin 30
 = 80 N.m
 max = BIAN = 160 N.m

sin 90 = 1 , 90 = 
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 = BIAN sin  = 0.4  2  200  10-4  1  Sin 30 = 8  10-3 N.m

|md| = IAN = 2  200  10-4  1 =0.04 A.m2
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