Page 9 - 6- اجابات نيوتن

‫إجابات‬
‫الفصل‬
‫الثانى‬

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2d X M X

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 2 r1 N1 = 2 r2 N2

 r2 N1 = 1
r1 4
= N2

NI

B= 2r

 B1  N1 r2  11  1
B2 N2 r1 4  4 16
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26.4 = 0.75
N = 2 r = 2   5.6

I= 2 Br = 28.2510-65.610-2
N 4  10-7  0.75

I = 0.98 A

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B +B =B   I   NI   NI
2d 2r2 2r1
 I  I  I
2r2 2r2 2r1  1 II
r2 r2 r1

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