Page 37 - Instrumen Soal HOTS

pH CH3COONa ...... ?
CH3COOH + NaOH → CH3COONa + H2O
Awal - Akhir
Sisa Maka :
[𝐺] [𝐺] [𝐺]
: 80 mmol : 80 mmol : -
= 𝑚𝑚𝑜𝑙 𝑉 𝑡𝑜𝑡𝑎𝑙
= 80 𝑚𝑚𝑜𝑙 200 𝑡𝑜𝑡𝑎𝑙
= 4 = 0,8 M 5
80 mmol 80 mmol
-
-
80 mmol 80 mmol
[𝑂𝐻−] =
√𝐾𝑤 [𝐺]. 𝑒 𝐾𝑎
[𝑂𝐻−] =
√10−14 [0,8]. 1 10−5
[𝑂𝐻−] =
√10−9 [0,8]
[𝑂𝐻−] = √8 10−5
pOH = − log √8 10−5
pOH =
−log[𝑂𝐻−]
Ditanaya :
29