pOH
maka pH pH
pH
=5−log √8
= 14 – pOH
=14–(5−log √8)
= 9 + 𝐥𝐨𝐠 √𝟖 = 9 + 2,828 = 11,828
• Percobaan 2
Diketahui : n CH3COOH
= 50 mL x 0,4 M = 20 mmol
n NaOH = 50 mL x 0,4 M = 20 mmol
Ka CH3COOH = 10-5 Vtotal = 100 mL
Ditanaya :
pH CH3COONa ...... ?
2
30