Page 182 - ISCI’2017
P. 182

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               II. Diagnostics data  A 3360  = (0 ||0 ||0 ||0 ||5). In accordance with the method of projections [1,2],
                                              
                                                               
            we construct possible projections  A  of the number  A 3360  =  (0 ||0 ||0 ||0 ||5):
                                               j
                   
                                     
                                                                                            
                                                       
                                                                         
                   A = (0 ||0 ||0 ||5),  A = (0 ||0 ||0 ||5),  A =  (0 ||0 ||0 ||5),  A = (0 ||0 ||0 ||5) и  A =  (0 ||0 ||0 ||0).
                                                        3
                                      2
                    1
                                                                          4
                                                                                             5
                                                                      
               The formula for calculating of the projections of values  A j PNS   in the PNS has the form  [1]
                                 n      
                        
                        A j PNS  =      ∑ aB ij     mod M =  j  (a B +  1 j  a B +  2 j  +  a B nj )mod M .   (11)
                                                                 ⋅
                                                                              ⋅
                                     ⋅
                                                        ⋅
                                    i
                                                                                          j
                                                       1
                                                               2
                                                                             n
                                 i= 1;  
                                 j= 1, n+ 1.  
                                                                                    
               In accordance with the formula (11) we can calculate all the values  A j PNS  . Next, we perform
                                              
             (n + 1)  a comparison of numbers  A j PNS   with the number  M =  M 0  / m n+ 1 . If among the projections
             
                                                                                
                                                        )
             A  have number no inside information [0, M  numerical range (i.e.  A ≥  M ), which contains k of
              i
                                                                                 k
            the correct numbers, than it is concluded that these  k  residual of the number  A are not distorted.
            Erroneous may be only the remains which are among the remaining [(n +     1) k  residual number
                                                                                        −
                                                                                           ]
             
             A SRC  . Set of the partial working base for a given SRC and set of partial orthogonal bases are presented
            in   [6-9]. So, we have that
                         
                                      ⋅
                                                                 ⋅
                                                        ⋅
                                                                                  ⋅
                                                                         ⋅
                        A 1PNS  =      4  a B 1 i ∑    mod M =  1  (a B +  11  aB +  21  a B +  31  aB 41 )mod M =  1
                                                                        3
                                     i
                                                       1
                                                                                 4
                                                               2
                                 i= 1   
                                =  (0 385 0 616 0 1100 5 980)mod1540⋅  +⋅  +⋅  + ⋅  = 280 < 420 .
                                                         
               We conclude that the residual  a  of числа  A  – it is possibly  a  distorted residual;
                                                                            1
                                                          1
                                              1
                        
                                                                 ⋅
                        A 2PNS  =      4  a B 2 i ∑    mod M =  2  (a B +  12  aB +  22  a B +  32  aB 42 )mod M =  2
                                                        ⋅
                                                                          ⋅
                                     ⋅
                                                                                   ⋅
                                                               2
                                                                                 4
                                                                        3
                                    i
                                                       1
                                 i= 1   
                                = (0 385 0 231 0 330 5 210)mod1155 1050⋅  +⋅  +⋅  + ⋅  =  > 420.
               Thus, we find that  a  accurate not distorted residual;
                                   2
                        
                                     ⋅
                                                        ⋅
                                                                                  ⋅
                                                                          ⋅
                                                                 ⋅
                        A    =      4  a B 3 i ∑    mod M =  3  (a B +  13  aB +  23  a B +  33  aB 43 )mod M =  3
                                                                                 4
                                                                2
                                                                        3
                                                       1
                                 3PNS  i= 1  i  
                                 =  (0 616 0 693 0 792 5 672)mod 924 588⋅  +⋅  +⋅  + ⋅  =  >  420 .
               We find that  a  accurate not distorted residual;
                             3
                        
                                                        ⋅
                                     ⋅
                                                                 ⋅
                                                                          ⋅
                        A 4PNS  =      4  a B 4 i ∑    mod M =  4  (a B +  14  aB +  24  a B +  34  aB 44 )mod M =  4
                                                                                   ⋅
                                                                                 4
                                                               2
                                                       1
                                    i
                                                                        3
                                 i= 1   
                                  (0 220 0 165 0 369 5 540)mod660⋅  +⋅  +⋅  + ⋅  =  60 <  420 .
                                                                     
               Conclusion: the residual  a  to modular  m  of number  A  – perhaps distorted residual  a
                                                                      4
                                         4
                                                                                                    4
                                                        4
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