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564                            C HAPTE R 8 I INTRODUCTION TO ALGEBRA


        PRACTICE 16                     Example 16      Simplify:  -21x - 52 + 412x + 22
        Simplify:
                                        Solution: First we use the distributive property to remove parentheses.
        -71x - 12 + 512x + 32

                                        –2(x-5)+4(2x+2)=–2(x)-(–2)(5)+4(2x)+4(2)                Apply the distributive
                                                                                                property.
                                                              =-2x + 10 + 8x + 8                Multiply.
                                                              = 6x + 18                         Combine like terms.
                                          Work Practice 16

                                       Objective      Finding Perimeter and Area

        PRACTICE 17                     Example 17      Find the perimeter of the triangle.

        Find the perimeter of the square.
                                                               2z feet     3z feet
                        2x
                     centimeters                                        5z feet
                                        Solution: Recall that the perimeter of a figure is the distance around the figure.
                                        To find the perimeter, then, we find the sum of the lengths of the sides. We use the
                                        letter P to represent perimeter.
                                            P = 2z + 3z + 5z
                                              = 10z                                             Don’t forget to
                                                            T                        insert proper units.
                                        The perimeter is 10z feet.
                                          Work Practice 17

        PRACTICE 18                     Example 18      Finding the Area of a Basketball Court
        Find the area of the rectangular
        garden.                         Find the area of this YMCA basketball court.




                                                                                           (2x  6) ft
          (12y  9) yards
                                3 yards
                                                                        45 ft
                                                                                                     #
                                        Solution: Recall how to find the area of a rectangle. Area = Length Width , or if
                                        A represents area, l represents length, and  represents width, we have A = l ww  #  .
                                                  #
                                            A = l w
                                              =45(2x-6)     Let l = 45 and w = (2x - 6) .
                                               = 90x - 270  Multiply.
                                        The area is (90x - 270)  square feet.
                                          Work Practice 18
                                                                                                                    Copyright 2012 Pearson Education, Inc.



                                        Don’t forget...

                                                           Area:               Perimeter:
        Answers                                            • surface enclosed  • distance around
        16. 3x + 22  17. 8x cm                             • measured in square units  • measured in units
        18. (36y + 27) sq yd
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