Page 88 - Basic College Mathematics with Early Integers
P. 88
S E C T ION 1. 7 I DIVIDING WHOLE NUMBERS 65
Check: 7089 # 8 + 5 = 56,717
∂ ∂ ∂ ∂
whole
# remainder
number divisor + = dividend
part
part
Work Practice 7
When the divisor has more than one digit, the same pattern applies. For example,
let’s find 1358 , 23.
5 135 , 23 = 5 with 20 left over. Our estimate is 5.
231358
– 115 5(23) = 115
208 135 - 115 = 20. Bring down the 8.
Now we continue estimating.
59 R 1 208 , 23 = 9 with 1 left over.
231358
-115
208
-207 9(23) = 207
1 208 - 207 = 1. The remainder is 1.
#
To check, see that 59 23 + 1 = 1358.
Example 8 Divide: 6819 , 17 PRACTICE 8
Divide: 8920 , 17
Solution: 401 R 2
176819
– 68 41172 = 68
01 Subtract and bring down the 1.
– 0 01172 = 0
19 Subtract and bring down the 9.
– 17 11172 = 17
2 Subtract.The reminder is 2.
#
To check, see that 401 17 + 2 = 6819.
Work Practice 8
Example 9 Divide: 51,600 , 403 PRACTICE 9
Divide: 33,282 , 678
Solution: 128 R 16
40351600
– 403 114032 = 403
1130 Subtract and bring down the 0.
– 806 214032 = 806
3240 Subtract and bring down the 0.
– 3224 814032 = 3224
16 Subtract.The remainder is 16.
#
To check, see that 128 403 + 16 = 51,600.
Answers
Work Practice 9 8. 524 R 12 9. 49 R 60

