Page 236 - Basic Electrical Engineering
P. 236

or,

                                             2V  − 3V  = 24                 (ii)
                                                1
                                                        2

               from (ii)










               Substituting V  in (i)
                                 2









               Putting value of V  in (i)
                                     1


                                               5V  − 3V  = 48
                                                          2
                                                  1
                or,                           5 × 8 − 3V  = 48
                                                           2
                                            3V  = 40 − 48 = −8
                                                2


















               To cross-check


                                           I  = I  + 6 = − 0.67 + 6 = 5.33 A
                                            2
                                                 3

                                                   2.10 DC TRANSIENTS
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