or, 2V − 3V = 24 (ii) 1 2 from (ii) Substituting V in (i) 2 Putting value of V in (i) 1 5V − 3V = 48 2 1 or, 5 × 8 − 3V = 48 2 3V = 40 − 48 = −8 2 To cross-check I = I + 6 = − 0.67 + 6 = 5.33 A 2 3 2.10 DC TRANSIENTS